(c-2)(c^2+2c+4)=0

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Solution for (c-2)(c^2+2c+4)=0 equation:


Simplifying
(c + -2)(c2 + 2c + 4) = 0

Reorder the terms:
(-2 + c)(c2 + 2c + 4) = 0

Reorder the terms:
(-2 + c)(4 + 2c + c2) = 0

Multiply (-2 + c) * (4 + 2c + c2)
(-2(4 + 2c + c2) + c(4 + 2c + c2)) = 0
((4 * -2 + 2c * -2 + c2 * -2) + c(4 + 2c + c2)) = 0
((-8 + -4c + -2c2) + c(4 + 2c + c2)) = 0
(-8 + -4c + -2c2 + (4 * c + 2c * c + c2 * c)) = 0
(-8 + -4c + -2c2 + (4c + 2c2 + c3)) = 0

Reorder the terms:
(-8 + -4c + 4c + -2c2 + 2c2 + c3) = 0

Combine like terms: -4c + 4c = 0
(-8 + 0 + -2c2 + 2c2 + c3) = 0
(-8 + -2c2 + 2c2 + c3) = 0

Combine like terms: -2c2 + 2c2 = 0
(-8 + 0 + c3) = 0
(-8 + c3) = 0

Solving
-8 + c3 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + c3 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + c3 = 0 + 8
c3 = 0 + 8

Combine like terms: 0 + 8 = 8
c3 = 8

Simplifying
c3 = 8

Reorder the terms:
-8 + c3 = 8 + -8

Combine like terms: 8 + -8 = 0
-8 + c3 = 0

The solution to this equation could not be determined.

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